Find Armstrong Number between 1 to 500 using loop

Armstrong numbers are those number whose sum of the cube of all digits equal to Original number.

i.e 153= (1x1x1 + 5x5x5 + 3x3x3)

void main()

{

     int i, sum=0, cube, num=0, neen=0, a;

    

     for(i=1; i<=500; i++)

     {

          neen = i;

          num=i;

          sum=0;

          while(num!=0)

          {

              cube=0;

              a=num%10;

              num=num/10;

              cube=a*a*a;

             

              sum=sum+cube;

          }

          if(neen == sum)

          printf("\n %d is Armstrong Number",neen);

     }

     getch();

}

OutPut:



Armstrong Number

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Program for displaying ASCII values of English Alphabets

#include “stdio.h”

int main()
{
     int i = 0;

     for( i = 65; i <= 122; i++)

     {

          if (i >= 91 && i <= 96) //to non-alphabet characters

          continue;

          printf("%c - %d",i,i);

          printf("\t");

     }

     getch();

     return 0;

}

 

Output:

ASCII values of English Alphabets





 

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